Django limit foreign key choices
WebAnd I need to limit the choices to show only "8 and 20" if the user is not staff. This is the model in models.py. class OrderMovements (models.Model): fk_workorder = models.ForeignKey (WorkOrder) status = models.IntegerField (choices=STATUS_CHOICES, default=1) timestamp = models.DateTimeField … WebJun 1, 2024 · 1. Foreign key choices in the admin can be limited via ModelAdmin.formfield_for_foreignkey (). During form instantiation, the current object (i.e. QuestionLogic) is stored on the request object that is available in the formfield_for_foreignkey () method. Note that the object is not stored on the ModelAdmin …
Django limit foreign key choices
Did you know?
WebAug 27, 2024 · 推荐答案. genericForeignkey尝试给您ForeignKey行为,但要与一种类型的 对象 相反,它们是为一组对象类型而做的 (这就是为什么使用2列定义它们,以保持<<<. … WebNov 10, 2010 · class unit (models.Model): name = models.CharField (max_length=200) class project (models.Model): name = models.CharField (max_length=200) class location (address): project = models.ForeignKey (project) class project_unit (models.Model): project = models.ForeignKey (project) unit = models.ForeignKey (unit) class location_unit …
WebAug 27, 2024 · 推荐答案. genericForeignkey尝试给您ForeignKey行为,但要与一种类型的 对象 相反,它们是为一组对象类型而做的 (这就是为什么使用2列定义它们,以保持<<<. GenericRelation是GenericForeignKey的反向关系,因为django不会自动为GenericForeignKeys (不同的C12>)创建反向关系,您必须 ... WebForeignKey. limit_choices_to ¶ Sets a limit to the available choices for this field when this field is rendered using a ModelForm or the admin (by default, all objects in the queryset …
WebOct 12, 2015 · I am running Django 1.1 and cannot get the "limit_choices_to" option for my ManytoManyField to work. I have two models: class MemberPhoto(ImageModel): title = models.CharField(_('title'), ... I want to access the foreign key and filtering queryset in django-admin. 0. Selecting a favourite image from a list of associated images in Django …
WebAug 6, 2024 · Dynamic choice for Foreign Key in Django Model Ask Question Asked 4 years, 8 months ago Modified 4 years, 8 months ago Viewed 803 times 0 I'm currently having some difficulty implementing dynamic choice for a field in my model. The model in question is as below.
WebJul 24, 2008 · I went to all the documentation, also I went to the IRC channel (BTW a great community) and they told me that is not possible to create a model and limit choices in a field where the 'current user' is in a ForeignKey. rose-wood completionsWebMar 21, 2024 · Limit/Filter Foreign Key Choices in Django Admin Ask Question Asked 5 years ago Modified 5 years ago Viewed 5k times 8 Consider an app where people can participate in a contest. I have a … rosewood communities greer scWeb2 days ago · I am a beginner in dango. I am trying to retrieve the price from the service and make a sum of all the prices. I am asking for help. logopedija/models.py storing samsung wasmachineWebApr 7, 2024 · how to limit foreign key choices in the form page? Ask Question Asked 1 year, 11 months ago Modified 1 year, 11 months ago Viewed 437 times 0 below are my models, I want to display only those groups in post form in which the user is joined in. Example: if I joined in "mcu" group then only that group should be displayed, how should … rosewood condo for saleWebMay 12, 2015 · 17. I am trying to limit choices for a field, by checking values of the two columns, share_holder and distributor. If either of them is true, then I want that choice. With the below version, I only get choices satisfying both conditions ('share_holder': True AND 'distributor': True). limit_choices_to= {'share_holder': True, 'distributor': True} rosewood condos charlotteWebI just came across ForeignKey.limit_choices_to in the Django docs. Not sure yet how it works, but it might be the right thing here. Update: ForeignKey.limit_choices_to allows one to specify either a constant, a callable or a Q object to restrict the allowable … rosewood community church columbia scWebJul 26, 2024 · use limit_choices_to on ForeignKey. check django docs for details and Q objects, app_label. you need to write proper app_label and model. This is just code snippet plus: I think you write wrong app_label. This can help you. from django.contrib.contenttypes.models import ContentType for c in ContentType.objects.all … storing safety razor